CIV E 444 - APPLIED HYDRAULICS
SPRING 2016
HOMEWORK No. 11 SOLUTION

  1. For a culvert type square edge with headwalls, use Ke = 0.5. Use KE = 1 for free outlet. Use ONLINE CULVERT for the given data.

    Results: Culvert diameter: D = 5 ft; critical depth yc = 4.209 ft; normal depth yn = 2.783 ft.

  2. Q = (2/3) (2g)1/2 C L (H13/2 - H23/2)

    H1 = 5 ft; d = 1 ft.

    H2 = H1 - d = 4 ft.

    d / H1 = 1/ 5 = 0.2

    From Fig. 7-11:   C = 0.7

    Qd = 1 = (2/3) (2 × 32.2)1/2 (0.7) (100) [(5)3/2 - (4)3/2] = 1,191 cfs.

    If gate opening is raised 0.5 ft:   d = 1.5 ft.

    H2 = H1 - d = 3.5 ft.

    d / H1 = 1.5/ 5 = 0.3

    From Fig. 7-11:   C = 0.684

    Qd = 1.5 = (2/3) (2 × 32.2)1/2 (0.684) (100) [(5)3/2 - (3.5)3/2] = 1,695 cfs.

  3. ΔE = 0.145 m, verified with ONLINECHANNEL12.

  4. Sequents depths y1 = 0.1 m, and y2 = 0.38 m, verified with ONLINECHANNEL16.

  5. ΔE = 0.145 m, verified with ONLINECHANNEL19.